Tim Reilly vs Alfred Flatow
Sydney, 1991 · Result 0–1 · Nimzo-Indian Defense: Normal Variation, Classical Defense (E48).
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Game details
- White
- Tim Reilly (2325)
- Black
- Alfred Flatow (2250)
- Result
- 0–1
- Event
- Sydney
- Year
- 1991
- Opening
- Nimzo-Indian Defense: Normal Variation, Classical Defense (E48)
About this chess game
This chess game between Tim Reilly (2325) and Alfred Flatow (2250) was played at Sydney in 1991 and finished 0–1. The opening was the Nimzo-Indian Defense: Normal Variation, Classical Defense (E48). You can replay the full game move by move on the interactive board above, or open it on the CipherChess analysis board to study every move with the Stockfish engine.
Looking for more Tim Reilly games or Alfred Flatow games? This Tim Reilly vs Alfred Flatow encounter is one of millions of chess games indexed in the CipherChess mega database. Browse both players' full records, the openings they play most, and head-to-head results, then load any game onto the board to prepare your own lines against the Nimzo-Indian Defense: Normal Variation, Classical Defense.
Frequently asked questions
Who won Tim Reilly vs Alfred Flatow?
Tim Reilly vs Alfred Flatow (1991) finished 0–1, a win for Alfred Flatow.
What opening was played in Tim Reilly vs Alfred Flatow?
The game opened with the Nimzo-Indian Defense: Normal Variation, Classical Defense (ECO E48).
Can I replay this chess game move by move?
Yes. Use the interactive board on this page to step through every move of Tim Reilly vs Alfred Flatow, or open it on the CipherChess analysis board to review it with the Stockfish engine.