Balasubramaniam Ramnathan vs Rahul Sangma
2. Hyderabad Open 2018, 2018 · Result ½–½ · Zukertort Opening (A05).
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Game details
- White
- Balasubramaniam Ramnathan (2096)
- Black
- Rahul Sangma (2297)
- Result
- ½–½
- Event
- 2. Hyderabad Open 2018
- Year
- 2018
- Opening
- Zukertort Opening (A05)
About this chess game
This chess game between Balasubramaniam Ramnathan (2096) and Rahul Sangma (2297) was played at 2. Hyderabad Open 2018 in 2018 and finished ½–½. The opening was the Zukertort Opening (A05). You can replay the full game move by move on the interactive board above, or open it on the CipherChess analysis board to study every move with the Stockfish engine.
Looking for more Balasubramaniam Ramnathan games or Rahul Sangma games? This Balasubramaniam Ramnathan vs Rahul Sangma encounter is one of millions of chess games indexed in the CipherChess mega database. Browse both players' full records, the openings they play most, and head-to-head results, then load any game onto the board to prepare your own lines against the Zukertort Opening.
Frequently asked questions
Who won Balasubramaniam Ramnathan vs Rahul Sangma?
Balasubramaniam Ramnathan vs Rahul Sangma (2018) finished ½–½, and the game was drawn.
What opening was played in Balasubramaniam Ramnathan vs Rahul Sangma?
The game opened with the Zukertort Opening (ECO A05).
Can I replay this chess game move by move?
Yes. Use the interactive board on this page to step through every move of Balasubramaniam Ramnathan vs Rahul Sangma, or open it on the CipherChess analysis board to review it with the Stockfish engine.