Kulkarni Rahul vs Christopher A Gibson
4NCL International 2018, 2018 · Result 1–0 · Sicilian Defense: Alapin Variation (B22).
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Game details
- White
- Kulkarni Rahul (1283)
- Black
- Christopher A Gibson (1924)
- Result
- 1–0
- Event
- 4NCL International 2018
- Year
- 2018
- Opening
- Sicilian Defense: Alapin Variation (B22)
About this chess game
This chess game between Kulkarni Rahul (1283) and Christopher A Gibson (1924) was played at 4NCL International 2018 in 2018 and finished 1–0. The opening was the Sicilian Defense: Alapin Variation (B22). You can replay the full game move by move on the interactive board above, or open it on the CipherChess analysis board to study every move with the Stockfish engine.
Looking for more Kulkarni Rahul games or Christopher A Gibson games? This Kulkarni Rahul vs Christopher A Gibson encounter is one of millions of chess games indexed in the CipherChess mega database. Browse both players' full records, the openings they play most, and head-to-head results, then load any game onto the board to prepare your own lines against the Sicilian Defense: Alapin Variation.
Frequently asked questions
Who won Kulkarni Rahul vs Christopher A Gibson?
Kulkarni Rahul vs Christopher A Gibson (2018) finished 1–0, a win for Kulkarni Rahul.
What opening was played in Kulkarni Rahul vs Christopher A Gibson?
The game opened with the Sicilian Defense: Alapin Variation (ECO B22).
Can I replay this chess game move by move?
Yes. Use the interactive board on this page to step through every move of Kulkarni Rahul vs Christopher A Gibson, or open it on the CipherChess analysis board to review it with the Stockfish engine.