Jamilur Rahman vs Ron Sammut
Manila, 1992 · Result ½–½ · Zukertort Opening (A06).
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Game details
- White
- Jamilur Rahman (2210)
- Black
- Ron Sammut (1842)
- Result
- ½–½
- Event
- Manila
- Year
- 1992
- Opening
- Zukertort Opening (A06)
About this chess game
This chess game between Jamilur Rahman (2210) and Ron Sammut (1842) was played at Manila in 1992 and finished ½–½. The opening was the Zukertort Opening (A06). You can replay the full game move by move on the interactive board above, or open it on the CipherChess analysis board to study every move with the Stockfish engine.
Looking for more Jamilur Rahman games or Ron Sammut games? This Jamilur Rahman vs Ron Sammut encounter is one of millions of chess games indexed in the CipherChess mega database. Browse both players' full records, the openings they play most, and head-to-head results, then load any game onto the board to prepare your own lines against the Zukertort Opening.
Frequently asked questions
Who won Jamilur Rahman vs Ron Sammut?
Jamilur Rahman vs Ron Sammut (1992) finished ½–½, and the game was drawn.
What opening was played in Jamilur Rahman vs Ron Sammut?
The game opened with the Zukertort Opening (ECO A06).
Can I replay this chess game move by move?
Yes. Use the interactive board on this page to step through every move of Jamilur Rahman vs Ron Sammut, or open it on the CipherChess analysis board to review it with the Stockfish engine.