Alexey Polschikov vs Hong Ming Teo
4. Big Rook Open 2024, 2024 · Result 1–0 · Nimzo-Indian Defense: Normal Variation, Ragozin Variation (E51).
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Game details
- White
- Alexey Polschikov (2389)
- Black
- Hong Ming Teo (2098)
- Result
- 1–0
- Event
- 4. Big Rook Open 2024
- Year
- 2024
- Opening
- Nimzo-Indian Defense: Normal Variation, Ragozin Variation (E51)
About this chess game
This chess game between Alexey Polschikov (2389) and Hong Ming Teo (2098) was played at 4. Big Rook Open 2024 in 2024 and finished 1–0. The opening was the Nimzo-Indian Defense: Normal Variation, Ragozin Variation (E51). You can replay the full game move by move on the interactive board above, or open it on the CipherChess analysis board to study every move with the Stockfish engine.
Looking for more Alexey Polschikov games or Hong Ming Teo games? This Alexey Polschikov vs Hong Ming Teo encounter is one of millions of chess games indexed in the CipherChess mega database. Browse both players' full records, the openings they play most, and head-to-head results, then load any game onto the board to prepare your own lines against the Nimzo-Indian Defense: Normal Variation, Ragozin Variation.
Frequently asked questions
Who won Alexey Polschikov vs Hong Ming Teo?
Alexey Polschikov vs Hong Ming Teo (2024) finished 1–0, a win for Alexey Polschikov.
What opening was played in Alexey Polschikov vs Hong Ming Teo?
The game opened with the Nimzo-Indian Defense: Normal Variation, Ragozin Variation (ECO E51).
Can I replay this chess game move by move?
Yes. Use the interactive board on this page to step through every move of Alexey Polschikov vs Hong Ming Teo, or open it on the CipherChess analysis board to review it with the Stockfish engine.