Alexey Polschikov vs Bogdan Lalic
30. Czech Rapid G1 2019, 2019 · Result 1–0 · English Opening: Symmetrical Variation (A30).
Turn this game into your next win
Replay Alexey Polschikov vs Bogdan Lalic with deep analysis, save the moments that matter, fold the ideas into your own opening repertoire, and drill the positions until they're second nature. CipherChess turns the games you study into the results you get — free to start.
Start Free on CipherChessMore Games By These Players
Game details
- White
- Alexey Polschikov (2375)
- Black
- Bogdan Lalic (2411)
- Result
- 1–0
- Event
- 30. Czech Rapid G1 2019
- Year
- 2019
- Opening
- English Opening: Symmetrical Variation (A30)
About this chess game
This chess game between Alexey Polschikov (2375) and Bogdan Lalic (2411) was played at 30. Czech Rapid G1 2019 in 2019 and finished 1–0. The opening was the English Opening: Symmetrical Variation (A30). You can replay the full game move by move on the interactive board above, or open it on the CipherChess analysis board to study every move with the Stockfish engine.
Looking for more Alexey Polschikov games or Bogdan Lalic games? This Alexey Polschikov vs Bogdan Lalic encounter is one of millions of chess games indexed in the CipherChess mega database. Browse both players' full records, the openings they play most, and head-to-head results, then load any game onto the board to prepare your own lines against the English Opening: Symmetrical Variation.
Frequently asked questions
Who won Alexey Polschikov vs Bogdan Lalic?
Alexey Polschikov vs Bogdan Lalic (2019) finished 1–0, a win for Alexey Polschikov.
What opening was played in Alexey Polschikov vs Bogdan Lalic?
The game opened with the English Opening: Symmetrical Variation (ECO A30).
Can I replay this chess game move by move?
Yes. Use the interactive board on this page to step through every move of Alexey Polschikov vs Bogdan Lalic, or open it on the CipherChess analysis board to review it with the Stockfish engine.