John C Pigott vs Nicholas Mark Kakuru
4NCL Div 2 2023-24, 2024 · Result ½–½ · Ruy Lopez: Morphy Defense, Anderssen Variation (C77).
Turn this game into your next win
Replay John C Pigott vs Nicholas Mark Kakuru with deep analysis, save the moments that matter, fold the ideas into your own opening repertoire, and drill the positions until they're second nature. CipherChess turns the games you study into the results you get — free to start.
Start Free on CipherChessMore Games By These Players
Game details
- White
- John C Pigott (2299)
- Black
- Nicholas Mark Kakuru (2145)
- Result
- ½–½
- Event
- 4NCL Div 2 2023-24
- Year
- 2024
- Opening
- Ruy Lopez: Morphy Defense, Anderssen Variation (C77)
About this chess game
This chess game between John C Pigott (2299) and Nicholas Mark Kakuru (2145) was played at 4NCL Div 2 2023-24 in 2024 and finished ½–½. The opening was the Ruy Lopez: Morphy Defense, Anderssen Variation (C77). You can replay the full game move by move on the interactive board above, or open it on the CipherChess analysis board to study every move with the Stockfish engine.
Looking for more John C Pigott games or Nicholas Mark Kakuru games? This John C Pigott vs Nicholas Mark Kakuru encounter is one of millions of chess games indexed in the CipherChess mega database. Browse both players' full records, the openings they play most, and head-to-head results, then load any game onto the board to prepare your own lines against the Ruy Lopez: Morphy Defense, Anderssen Variation.
Frequently asked questions
Who won John C Pigott vs Nicholas Mark Kakuru?
John C Pigott vs Nicholas Mark Kakuru (2024) finished ½–½, and the game was drawn.
What opening was played in John C Pigott vs Nicholas Mark Kakuru?
The game opened with the Ruy Lopez: Morphy Defense, Anderssen Variation (ECO C77).
Can I replay this chess game move by move?
Yes. Use the interactive board on this page to step through every move of John C Pigott vs Nicholas Mark Kakuru, or open it on the CipherChess analysis board to review it with the Stockfish engine.