Andrew Peredun vs Tyrell Harriott
13. Philadelphia Int, 2019 · Result 1–0 · Old Indian Defense: Normal Variation (A55).
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Game details
- White
- Andrew Peredun (2344)
- Black
- Tyrell Harriott (2003)
- Result
- 1–0
- Event
- 13. Philadelphia Int
- Year
- 2019
- Opening
- Old Indian Defense: Normal Variation (A55)
About this chess game
This chess game between Andrew Peredun (2344) and Tyrell Harriott (2003) was played at 13. Philadelphia Int in 2019 and finished 1–0. The opening was the Old Indian Defense: Normal Variation (A55). You can replay the full game move by move on the interactive board above, or open it on the CipherChess analysis board to study every move with the Stockfish engine.
Looking for more Andrew Peredun games or Tyrell Harriott games? This Andrew Peredun vs Tyrell Harriott encounter is one of millions of chess games indexed in the CipherChess mega database. Browse both players' full records, the openings they play most, and head-to-head results, then load any game onto the board to prepare your own lines against the Old Indian Defense: Normal Variation.
Frequently asked questions
Who won Andrew Peredun vs Tyrell Harriott?
Andrew Peredun vs Tyrell Harriott (2019) finished 1–0, a win for Andrew Peredun.
What opening was played in Andrew Peredun vs Tyrell Harriott?
The game opened with the Old Indian Defense: Normal Variation (ECO A55).
Can I replay this chess game move by move?
Yes. Use the interactive board on this page to step through every move of Andrew Peredun vs Tyrell Harriott, or open it on the CipherChess analysis board to review it with the Stockfish engine.