Alexandros Papasimakopoulos vs Igor Ryabov

4. Alexander the Great Open, 2012 · Result 1–0 · Indian Defense: Budapest Defense (A52).

Igor Ryabov19490

Alexandros Papasimakopoulos20451

Notation · 91 moves

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Game details

White: Alexandros Papasimakopoulos (2045)
Black: Igor Ryabov (1949)
Result: 1–0
Event: 4. Alexander the Great Open
Year: 2012
Opening: Indian Defense: Budapest Defense (A52)

About this chess game

This chess game between Alexandros Papasimakopoulos (2045) and Igor Ryabov (1949) was played at 4. Alexander the Great Open in 2012 and finished 1–0. The opening was the Indian Defense: Budapest Defense (A52). You can replay the full game move by move on the interactive board above, or open it on the CipherChess analysis board to study every move with the Stockfish engine.

Looking for more Alexandros Papasimakopoulos games or Igor Ryabov games? This Alexandros Papasimakopoulos vs Igor Ryabov encounter is one of millions of chess games indexed in the CipherChess mega database. Browse both players' full records, the openings they play most, and head-to-head results, then load any game onto the board to prepare your own lines against the Indian Defense: Budapest Defense.

Frequently asked questions

Who won Alexandros Papasimakopoulos vs Igor Ryabov?

Alexandros Papasimakopoulos vs Igor Ryabov (2012) finished 1–0, a win for Alexandros Papasimakopoulos.

What opening was played in Alexandros Papasimakopoulos vs Igor Ryabov?

The game opened with the Indian Defense: Budapest Defense (ECO A52).

Can I replay this chess game move by move?

Yes. Use the interactive board on this page to step through every move of Alexandros Papasimakopoulos vs Igor Ryabov, or open it on the CipherChess analysis board to review it with the Stockfish engine.