Mario Palladino vs Hans-Jürgen Rund
WS/M/749, 2019 · Result ½–½ · Nimzo-Indian Defense: Classical Variation, Noa Variation (E34).
Turn this game into your next win
Replay Mario Palladino vs Hans-Jürgen Rund with deep analysis, save the moments that matter, fold the ideas into your own opening repertoire, and drill the positions until they're second nature. CipherChess turns the games you study into the results you get — free to start.
Start Free on CipherChessMore Games By These Players
Game details
- White
- Mario Palladino (1475)
- Black
- Hans-Jürgen Rund (2165)
- Result
- ½–½
- Event
- WS/M/749
- Year
- 2019
- Opening
- Nimzo-Indian Defense: Classical Variation, Noa Variation (E34)
About this chess game
This chess game between Mario Palladino (1475) and Hans-Jürgen Rund (2165) was played at WS/M/749 in 2019 and finished ½–½. The opening was the Nimzo-Indian Defense: Classical Variation, Noa Variation (E34). You can replay the full game move by move on the interactive board above, or open it on the CipherChess analysis board to study every move with the Stockfish engine.
Looking for more Mario Palladino games or Hans-Jürgen Rund games? This Mario Palladino vs Hans-Jürgen Rund encounter is one of millions of chess games indexed in the CipherChess mega database. Browse both players' full records, the openings they play most, and head-to-head results, then load any game onto the board to prepare your own lines against the Nimzo-Indian Defense: Classical Variation, Noa Variation.
Frequently asked questions
Who won Mario Palladino vs Hans-Jürgen Rund?
Mario Palladino vs Hans-Jürgen Rund (2019) finished ½–½, and the game was drawn.
What opening was played in Mario Palladino vs Hans-Jürgen Rund?
The game opened with the Nimzo-Indian Defense: Classical Variation, Noa Variation (ECO E34).
Can I replay this chess game move by move?
Yes. Use the interactive board on this page to step through every move of Mario Palladino vs Hans-Jürgen Rund, or open it on the CipherChess analysis board to review it with the Stockfish engine.