Tamar Pachulia vs Kornelia Albert
Rimavska Sobota, 1992 · Result 1–0 · Zukertort Opening (A05).
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Game details
- White
- Tamar Pachulia (2060)
- Black
- Kornelia Albert (2130)
- Result
- 1–0
- Event
- Rimavska Sobota
- Year
- 1992
- Opening
- Zukertort Opening (A05)
About this chess game
This chess game between Tamar Pachulia (2060) and Kornelia Albert (2130) was played at Rimavska Sobota in 1992 and finished 1–0. The opening was the Zukertort Opening (A05). You can replay the full game move by move on the interactive board above, or open it on the CipherChess analysis board to study every move with the Stockfish engine.
Looking for more Tamar Pachulia games or Kornelia Albert games? This Tamar Pachulia vs Kornelia Albert encounter is one of millions of chess games indexed in the CipherChess mega database. Browse both players' full records, the openings they play most, and head-to-head results, then load any game onto the board to prepare your own lines against the Zukertort Opening.
Frequently asked questions
Who won Tamar Pachulia vs Kornelia Albert?
Tamar Pachulia vs Kornelia Albert (1992) finished 1–0, a win for Tamar Pachulia.
What opening was played in Tamar Pachulia vs Kornelia Albert?
The game opened with the Zukertort Opening (ECO A05).
Can I replay this chess game move by move?
Yes. Use the interactive board on this page to step through every move of Tamar Pachulia vs Kornelia Albert, or open it on the CipherChess analysis board to review it with the Stockfish engine.