Cintia Otero Campos vs Adhara Rodriguez Redondo
2018 · Result 0–1 · Queen's Pawn Game: Zukertort Variation (D02).
Turn this game into your next win
Replay Cintia Otero Campos vs Adhara Rodriguez Redondo with deep analysis, save the moments that matter, fold the ideas into your own opening repertoire, and drill the positions until they're second nature. CipherChess turns the games you study into the results you get — free to start.
Start Free on CipherChessMore Games By These Players
Game details
- White
- Cintia Otero Campos (1426)
- Black
- Adhara Rodriguez Redondo (1906)
- Result
- 0–1
- Year
- 2018
- Opening
- Queen's Pawn Game: Zukertort Variation (D02)
About this chess game
This chess game between Cintia Otero Campos (1426) and Adhara Rodriguez Redondo (1906) was played in 2018 and finished 0–1. The opening was the Queen's Pawn Game: Zukertort Variation (D02). You can replay the full game move by move on the interactive board above, or open it on the CipherChess analysis board to study every move with the Stockfish engine.
Looking for more Cintia Otero Campos games or Adhara Rodriguez Redondo games? This Cintia Otero Campos vs Adhara Rodriguez Redondo encounter is one of millions of chess games indexed in the CipherChess mega database. Browse both players' full records, the openings they play most, and head-to-head results, then load any game onto the board to prepare your own lines against the Queen's Pawn Game: Zukertort Variation.
Frequently asked questions
Who won Cintia Otero Campos vs Adhara Rodriguez Redondo?
Cintia Otero Campos vs Adhara Rodriguez Redondo (2018) finished 0–1, a win for Adhara Rodriguez Redondo.
What opening was played in Cintia Otero Campos vs Adhara Rodriguez Redondo?
The game opened with the Queen's Pawn Game: Zukertort Variation (ECO D02).
Can I replay this chess game move by move?
Yes. Use the interactive board on this page to step through every move of Cintia Otero Campos vs Adhara Rodriguez Redondo, or open it on the CipherChess analysis board to review it with the Stockfish engine.