Milton Kasuo Okamura vs Marcio De Lucca Cardoso
2019 · Result 0–1 · Nimzo-Indian Defense: Normal Variation (E46).
Turn this game into your next win
Replay Milton Kasuo Okamura vs Marcio De Lucca Cardoso with deep analysis, save the moments that matter, fold the ideas into your own opening repertoire, and drill the positions until they're second nature. CipherChess turns the games you study into the results you get — free to start.
Start Free on CipherChessMore Games By These Players
Game details
- White
- Milton Kasuo Okamura (1955)
- Black
- Marcio De Lucca Cardoso (1877)
- Result
- 0–1
- Year
- 2019
- Opening
- Nimzo-Indian Defense: Normal Variation (E46)
About this chess game
This chess game between Milton Kasuo Okamura (1955) and Marcio De Lucca Cardoso (1877) was played in 2019 and finished 0–1. The opening was the Nimzo-Indian Defense: Normal Variation (E46). You can replay the full game move by move on the interactive board above, or open it on the CipherChess analysis board to study every move with the Stockfish engine.
Looking for more Milton Kasuo Okamura games or Marcio De Lucca Cardoso games? This Milton Kasuo Okamura vs Marcio De Lucca Cardoso encounter is one of millions of chess games indexed in the CipherChess mega database. Browse both players' full records, the openings they play most, and head-to-head results, then load any game onto the board to prepare your own lines against the Nimzo-Indian Defense: Normal Variation.
Frequently asked questions
Who won Milton Kasuo Okamura vs Marcio De Lucca Cardoso?
Milton Kasuo Okamura vs Marcio De Lucca Cardoso (2019) finished 0–1, a win for Marcio De Lucca Cardoso.
What opening was played in Milton Kasuo Okamura vs Marcio De Lucca Cardoso?
The game opened with the Nimzo-Indian Defense: Normal Variation (ECO E46).
Can I replay this chess game move by move?
Yes. Use the interactive board on this page to step through every move of Milton Kasuo Okamura vs Marcio De Lucca Cardoso, or open it on the CipherChess analysis board to review it with the Stockfish engine.