Wilfred Nyberg vs Vytautas Boreika
EU/SenC1 pr 3, 2021 · Result ½–½ · Vienna Game: Stanley Variation, Three Knights Variation (C28).
Turn this game into your next win
Replay Wilfred Nyberg vs Vytautas Boreika with deep analysis, save the moments that matter, fold the ideas into your own opening repertoire, and drill the positions until they're second nature. CipherChess turns the games you study into the results you get — free to start.
Start Free on CipherChessMore Games By These Players
Game details
- White
- Wilfred Nyberg (2292)
- Black
- Vytautas Boreika (2285)
- Result
- ½–½
- Event
- EU/SenC1 pr 3
- Year
- 2021
- Opening
- Vienna Game: Stanley Variation, Three Knights Variation (C28)
About this chess game
This chess game between Wilfred Nyberg (2292) and Vytautas Boreika (2285) was played at EU/SenC1 pr 3 in 2021 and finished ½–½. The opening was the Vienna Game: Stanley Variation, Three Knights Variation (C28). You can replay the full game move by move on the interactive board above, or open it on the CipherChess analysis board to study every move with the Stockfish engine.
Looking for more Wilfred Nyberg games or Vytautas Boreika games? This Wilfred Nyberg vs Vytautas Boreika encounter is one of millions of chess games indexed in the CipherChess mega database. Browse both players' full records, the openings they play most, and head-to-head results, then load any game onto the board to prepare your own lines against the Vienna Game: Stanley Variation, Three Knights Variation.
Frequently asked questions
Who won Wilfred Nyberg vs Vytautas Boreika?
Wilfred Nyberg vs Vytautas Boreika (2021) finished ½–½, and the game was drawn.
What opening was played in Wilfred Nyberg vs Vytautas Boreika?
The game opened with the Vienna Game: Stanley Variation, Three Knights Variation (ECO C28).
Can I replay this chess game move by move?
Yes. Use the interactive board on this page to step through every move of Wilfred Nyberg vs Vytautas Boreika, or open it on the CipherChess analysis board to review it with the Stockfish engine.