Rolando Nolte vs De Dao Linson Lim
5. Penang Open 2013, 2013 · Result 1–0 · Zukertort Opening (A05).
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Game details
- White
- Rolando Nolte (2425)
- Black
- De Dao Linson Lim (1815)
- Result
- 1–0
- Event
- 5. Penang Open 2013
- Year
- 2013
- Opening
- Zukertort Opening (A05)
About this chess game
This chess game between Rolando Nolte (2425) and De Dao Linson Lim (1815) was played at 5. Penang Open 2013 in 2013 and finished 1–0. The opening was the Zukertort Opening (A05). You can replay the full game move by move on the interactive board above, or open it on the CipherChess analysis board to study every move with the Stockfish engine.
Looking for more Rolando Nolte games or De Dao Linson Lim games? This Rolando Nolte vs De Dao Linson Lim encounter is one of millions of chess games indexed in the CipherChess mega database. Browse both players' full records, the openings they play most, and head-to-head results, then load any game onto the board to prepare your own lines against the Zukertort Opening.
Frequently asked questions
Who won Rolando Nolte vs De Dao Linson Lim?
Rolando Nolte vs De Dao Linson Lim (2013) finished 1–0, a win for Rolando Nolte.
What opening was played in Rolando Nolte vs De Dao Linson Lim?
The game opened with the Zukertort Opening (ECO A05).
Can I replay this chess game move by move?
Yes. Use the interactive board on this page to step through every move of Rolando Nolte vs De Dao Linson Lim, or open it on the CipherChess analysis board to review it with the Stockfish engine.