Thomas Niedermeier vs Stephan Steinmueller
2014 · Result 1–0 · Sicilian Defense: Kan Variation, Knight Variation (B43).
Turn this game into your next win
Replay Thomas Niedermeier vs Stephan Steinmueller with deep analysis, save the moments that matter, fold the ideas into your own opening repertoire, and drill the positions until they're second nature. CipherChess turns the games you study into the results you get — free to start.
Start Free on CipherChessMore Games By These Players
Game details
- White
- Thomas Niedermeier (2157)
- Black
- Stephan Steinmueller (2079)
- Result
- 1–0
- Year
- 2014
- Opening
- Sicilian Defense: Kan Variation, Knight Variation (B43)
About this chess game
This chess game between Thomas Niedermeier (2157) and Stephan Steinmueller (2079) was played in 2014 and finished 1–0. The opening was the Sicilian Defense: Kan Variation, Knight Variation (B43). You can replay the full game move by move on the interactive board above, or open it on the CipherChess analysis board to study every move with the Stockfish engine.
Looking for more Thomas Niedermeier games or Stephan Steinmueller games? This Thomas Niedermeier vs Stephan Steinmueller encounter is one of millions of chess games indexed in the CipherChess mega database. Browse both players' full records, the openings they play most, and head-to-head results, then load any game onto the board to prepare your own lines against the Sicilian Defense: Kan Variation, Knight Variation.
Frequently asked questions
Who won Thomas Niedermeier vs Stephan Steinmueller?
Thomas Niedermeier vs Stephan Steinmueller (2014) finished 1–0, a win for Thomas Niedermeier.
What opening was played in Thomas Niedermeier vs Stephan Steinmueller?
The game opened with the Sicilian Defense: Kan Variation, Knight Variation (ECO B43).
Can I replay this chess game move by move?
Yes. Use the interactive board on this page to step through every move of Thomas Niedermeier vs Stephan Steinmueller, or open it on the CipherChess analysis board to review it with the Stockfish engine.