Rohan Shan Tze Navaratnam vs Manjula Srinath Rathnayaka
Budapest Spring Open 2019, 2019 · Result 0–1 · French Defense: McCutcheon Variation, Duras Variation (C12).
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Game details
- White
- Rohan Shan Tze Navaratnam (2068)
- Black
- Manjula Srinath Rathnayaka (1180)
- Result
- 0–1
- Event
- Budapest Spring Open 2019
- Year
- 2019
- Opening
- French Defense: McCutcheon Variation, Duras Variation (C12)
About this chess game
This chess game between Rohan Shan Tze Navaratnam (2068) and Manjula Srinath Rathnayaka (1180) was played at Budapest Spring Open 2019 in 2019 and finished 0–1. The opening was the French Defense: McCutcheon Variation, Duras Variation (C12). You can replay the full game move by move on the interactive board above, or open it on the CipherChess analysis board to study every move with the Stockfish engine.
Looking for more Rohan Shan Tze Navaratnam games or Manjula Srinath Rathnayaka games? This Rohan Shan Tze Navaratnam vs Manjula Srinath Rathnayaka encounter is one of millions of chess games indexed in the CipherChess mega database. Browse both players' full records, the openings they play most, and head-to-head results, then load any game onto the board to prepare your own lines against the French Defense: McCutcheon Variation, Duras Variation.
Frequently asked questions
Who won Rohan Shan Tze Navaratnam vs Manjula Srinath Rathnayaka?
Rohan Shan Tze Navaratnam vs Manjula Srinath Rathnayaka (2019) finished 0–1, a win for Manjula Srinath Rathnayaka.
What opening was played in Rohan Shan Tze Navaratnam vs Manjula Srinath Rathnayaka?
The game opened with the French Defense: McCutcheon Variation, Duras Variation (ECO C12).
Can I replay this chess game move by move?
Yes. Use the interactive board on this page to step through every move of Rohan Shan Tze Navaratnam vs Manjula Srinath Rathnayaka, or open it on the CipherChess analysis board to review it with the Stockfish engine.