Arkadij Naiditsch vs Angel Espinosa Aranda
TCh-ESP Div 1 2018, 2018 · Result 1–0 · French Defense: Classical Variation (C11).
Turn this game into your next win
Replay Arkadij Naiditsch vs Angel Espinosa Aranda with deep analysis, save the moments that matter, fold the ideas into your own opening repertoire, and drill the positions until they're second nature. CipherChess turns the games you study into the results you get — free to start.
Start Free on CipherChessMore Games By These Players
Game details
- White
- Arkadij Naiditsch (2711)
- Black
- Angel Espinosa Aranda (2451)
- Result
- 1–0
- Event
- TCh-ESP Div 1 2018
- Year
- 2018
- Opening
- French Defense: Classical Variation (C11)
About this chess game
This chess game between Arkadij Naiditsch (2711) and Angel Espinosa Aranda (2451) was played at TCh-ESP Div 1 2018 in 2018 and finished 1–0. The opening was the French Defense: Classical Variation (C11). You can replay the full game move by move on the interactive board above, or open it on the CipherChess analysis board to study every move with the Stockfish engine.
Looking for more Arkadij Naiditsch games or Angel Espinosa Aranda games? This Arkadij Naiditsch vs Angel Espinosa Aranda encounter is one of millions of chess games indexed in the CipherChess mega database. Browse both players' full records, the openings they play most, and head-to-head results, then load any game onto the board to prepare your own lines against the French Defense: Classical Variation.
Frequently asked questions
Who won Arkadij Naiditsch vs Angel Espinosa Aranda?
Arkadij Naiditsch vs Angel Espinosa Aranda (2018) finished 1–0, a win for Arkadij Naiditsch.
What opening was played in Arkadij Naiditsch vs Angel Espinosa Aranda?
The game opened with the French Defense: Classical Variation (ECO C11).
Can I replay this chess game move by move?
Yes. Use the interactive board on this page to step through every move of Arkadij Naiditsch vs Angel Espinosa Aranda, or open it on the CipherChess analysis board to review it with the Stockfish engine.