Romulo Rodrigues Mota vs Alexandre Letizio Vieira
2018 · Result 1–0 · Queen's Pawn Game (D00).
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Game details
- White
- Romulo Rodrigues Mota (1928)
- Black
- Alexandre Letizio Vieira (1817)
- Result
- 1–0
- Year
- 2018
- Opening
- Queen's Pawn Game (D00)
About this chess game
This chess game between Romulo Rodrigues Mota (1928) and Alexandre Letizio Vieira (1817) was played in 2018 and finished 1–0. The opening was the Queen's Pawn Game (D00). You can replay the full game move by move on the interactive board above, or open it on the CipherChess analysis board to study every move with the Stockfish engine.
Looking for more Romulo Rodrigues Mota games or Alexandre Letizio Vieira games? This Romulo Rodrigues Mota vs Alexandre Letizio Vieira encounter is one of millions of chess games indexed in the CipherChess mega database. Browse both players' full records, the openings they play most, and head-to-head results, then load any game onto the board to prepare your own lines against the Queen's Pawn Game.
Frequently asked questions
Who won Romulo Rodrigues Mota vs Alexandre Letizio Vieira?
Romulo Rodrigues Mota vs Alexandre Letizio Vieira (2018) finished 1–0, a win for Romulo Rodrigues Mota.
What opening was played in Romulo Rodrigues Mota vs Alexandre Letizio Vieira?
The game opened with the Queen's Pawn Game (ECO D00).
Can I replay this chess game move by move?
Yes. Use the interactive board on this page to step through every move of Romulo Rodrigues Mota vs Alexandre Letizio Vieira, or open it on the CipherChess analysis board to review it with the Stockfish engine.