Harold Morton vs Alexander Kevitz
New York ch-USA, 1936 · Result 0–1 · Indian Defense (A45).
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Game details
- White
- Harold Morton
- Black
- Alexander Kevitz
- Result
- 0–1
- Event
- New York ch-USA
- Year
- 1936
- Opening
- Indian Defense (A45)
About this chess game
This chess game between Harold Morton and Alexander Kevitz was played at New York ch-USA in 1936 and finished 0–1. The opening was the Indian Defense (A45). You can replay the full game move by move on the interactive board above, or open it on the CipherChess analysis board to study every move with the Stockfish engine.
Looking for more Harold Morton games or Alexander Kevitz games? This Harold Morton vs Alexander Kevitz encounter is one of millions of chess games indexed in the CipherChess mega database. Browse both players' full records, the openings they play most, and head-to-head results, then load any game onto the board to prepare your own lines against the Indian Defense.
Frequently asked questions
Who won Harold Morton vs Alexander Kevitz?
Harold Morton vs Alexander Kevitz (1936) finished 0–1, a win for Alexander Kevitz.
What opening was played in Harold Morton vs Alexander Kevitz?
The game opened with the Indian Defense (ECO A45).
Can I replay this chess game move by move?
Yes. Use the interactive board on this page to step through every move of Harold Morton vs Alexander Kevitz, or open it on the CipherChess analysis board to review it with the Stockfish engine.