David W Moody vs Ira Lee Riddle
Jacksonville, Fla., 1990 · Result 1–0 · Petrov's Defense (C42).
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Game details
- White
- David W Moody (2112)
- Black
- Ira Lee Riddle (1522)
- Result
- 1–0
- Event
- Jacksonville, Fla.
- Year
- 1990
- Opening
- Petrov's Defense (C42)
About this chess game
This chess game between David W Moody (2112) and Ira Lee Riddle (1522) was played at Jacksonville, Fla. in 1990 and finished 1–0. The opening was the Petrov's Defense (C42). You can replay the full game move by move on the interactive board above, or open it on the CipherChess analysis board to study every move with the Stockfish engine.
Looking for more David W Moody games or Ira Lee Riddle games? This David W Moody vs Ira Lee Riddle encounter is one of millions of chess games indexed in the CipherChess mega database. Browse both players' full records, the openings they play most, and head-to-head results, then load any game onto the board to prepare your own lines against the Petrov's Defense.
Frequently asked questions
Who won David W Moody vs Ira Lee Riddle?
David W Moody vs Ira Lee Riddle (1990) finished 1–0, a win for David W Moody.
What opening was played in David W Moody vs Ira Lee Riddle?
The game opened with the Petrov's Defense (ECO C42).
Can I replay this chess game move by move?
Yes. Use the interactive board on this page to step through every move of David W Moody vs Ira Lee Riddle, or open it on the CipherChess analysis board to review it with the Stockfish engine.