Roland Molnar vs Ferenc Szaz
2008 · Result ½–½ · Indian Defense: Przepiorka Variation (A49).
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Game details
- White
- Roland Molnar (2028)
- Black
- Ferenc Szaz (2188)
- Result
- ½–½
- Year
- 2008
- Opening
- Indian Defense: Przepiorka Variation (A49)
About this chess game
This chess game between Roland Molnar (2028) and Ferenc Szaz (2188) was played in 2008 and finished ½–½. The opening was the Indian Defense: Przepiorka Variation (A49). You can replay the full game move by move on the interactive board above, or open it on the CipherChess analysis board to study every move with the Stockfish engine.
Looking for more Roland Molnar games or Ferenc Szaz games? This Roland Molnar vs Ferenc Szaz encounter is one of millions of chess games indexed in the CipherChess mega database. Browse both players' full records, the openings they play most, and head-to-head results, then load any game onto the board to prepare your own lines against the Indian Defense: Przepiorka Variation.
Frequently asked questions
Who won Roland Molnar vs Ferenc Szaz?
Roland Molnar vs Ferenc Szaz (2008) finished ½–½, and the game was drawn.
What opening was played in Roland Molnar vs Ferenc Szaz?
The game opened with the Indian Defense: Przepiorka Variation (ECO A49).
Can I replay this chess game move by move?
Yes. Use the interactive board on this page to step through every move of Roland Molnar vs Ferenc Szaz, or open it on the CipherChess analysis board to review it with the Stockfish engine.