Georg Mohr vs Fred Wegerer
34. St Veit Open 2015, 2015 · Result 1–0 · English Opening: Symmetrical Variation, Ultra-Symmetrical Variation (A36).
Turn this game into your next win
Replay Georg Mohr vs Fred Wegerer with deep analysis, save the moments that matter, fold the ideas into your own opening repertoire, and drill the positions until they're second nature. CipherChess turns the games you study into the results you get — free to start.
Start Free on CipherChessMore Games By These Players
Game details
- White
- Georg Mohr (2459)
- Black
- Fred Wegerer (2111)
- Result
- 1–0
- Event
- 34. St Veit Open 2015
- Year
- 2015
- Opening
- English Opening: Symmetrical Variation, Ultra-Symmetrical Variation (A36)
About this chess game
This chess game between Georg Mohr (2459) and Fred Wegerer (2111) was played at 34. St Veit Open 2015 in 2015 and finished 1–0. The opening was the English Opening: Symmetrical Variation, Ultra-Symmetrical Variation (A36). You can replay the full game move by move on the interactive board above, or open it on the CipherChess analysis board to study every move with the Stockfish engine.
Looking for more Georg Mohr games or Fred Wegerer games? This Georg Mohr vs Fred Wegerer encounter is one of millions of chess games indexed in the CipherChess mega database. Browse both players' full records, the openings they play most, and head-to-head results, then load any game onto the board to prepare your own lines against the English Opening: Symmetrical Variation, Ultra-Symmetrical Variation.
Frequently asked questions
Who won Georg Mohr vs Fred Wegerer?
Georg Mohr vs Fred Wegerer (2015) finished 1–0, a win for Georg Mohr.
What opening was played in Georg Mohr vs Fred Wegerer?
The game opened with the English Opening: Symmetrical Variation, Ultra-Symmetrical Variation (ECO A36).
Can I replay this chess game move by move?
Yes. Use the interactive board on this page to step through every move of Georg Mohr vs Fred Wegerer, or open it on the CipherChess analysis board to review it with the Stockfish engine.