Nisha Mohota vs Lukas Sikora
34. Czech Rapid G1 2023, 2023 · Result 0–1 · Nimzo-Indian Defense: Rubinstein System, Rubinstein Variation (E42).
Turn this game into your next win
Replay Nisha Mohota vs Lukas Sikora with deep analysis, save the moments that matter, fold the ideas into your own opening repertoire, and drill the positions until they're second nature. CipherChess turns the games you study into the results you get — free to start.
Start Free on CipherChessMore Games By These Players
Game details
- White
- Nisha Mohota (2163)
- Black
- Lukas Sikora (1901)
- Result
- 0–1
- Event
- 34. Czech Rapid G1 2023
- Year
- 2023
- Opening
- Nimzo-Indian Defense: Rubinstein System, Rubinstein Variation (E42)
About this chess game
This chess game between Nisha Mohota (2163) and Lukas Sikora (1901) was played at 34. Czech Rapid G1 2023 in 2023 and finished 0–1. The opening was the Nimzo-Indian Defense: Rubinstein System, Rubinstein Variation (E42). You can replay the full game move by move on the interactive board above, or open it on the CipherChess analysis board to study every move with the Stockfish engine.
Looking for more Nisha Mohota games or Lukas Sikora games? This Nisha Mohota vs Lukas Sikora encounter is one of millions of chess games indexed in the CipherChess mega database. Browse both players' full records, the openings they play most, and head-to-head results, then load any game onto the board to prepare your own lines against the Nimzo-Indian Defense: Rubinstein System, Rubinstein Variation.
Frequently asked questions
Who won Nisha Mohota vs Lukas Sikora?
Nisha Mohota vs Lukas Sikora (2023) finished 0–1, a win for Lukas Sikora.
What opening was played in Nisha Mohota vs Lukas Sikora?
The game opened with the Nimzo-Indian Defense: Rubinstein System, Rubinstein Variation (ECO E42).
Can I replay this chess game move by move?
Yes. Use the interactive board on this page to step through every move of Nisha Mohota vs Lukas Sikora, or open it on the CipherChess analysis board to review it with the Stockfish engine.