Hana Modrova vs Gerrit Harmsen
Bohemians-Utrecht, 1990 · Result 0–1 · East Indian Defense (A48).
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Game details
- White
- Hana Modrova (2085)
- Black
- Gerrit Harmsen
- Result
- 0–1
- Event
- Bohemians-Utrecht
- Year
- 1990
- Opening
- East Indian Defense (A48)
About this chess game
This chess game between Hana Modrova (2085) and Gerrit Harmsen was played at Bohemians-Utrecht in 1990 and finished 0–1. The opening was the East Indian Defense (A48). You can replay the full game move by move on the interactive board above, or open it on the CipherChess analysis board to study every move with the Stockfish engine.
Looking for more Hana Modrova games or Gerrit Harmsen games? This Hana Modrova vs Gerrit Harmsen encounter is one of millions of chess games indexed in the CipherChess mega database. Browse both players' full records, the openings they play most, and head-to-head results, then load any game onto the board to prepare your own lines against the East Indian Defense.
Frequently asked questions
Who won Hana Modrova vs Gerrit Harmsen?
Hana Modrova vs Gerrit Harmsen (1990) finished 0–1, a win for Gerrit Harmsen.
What opening was played in Hana Modrova vs Gerrit Harmsen?
The game opened with the East Indian Defense (ECO A48).
Can I replay this chess game move by move?
Yes. Use the interactive board on this page to step through every move of Hana Modrova vs Gerrit Harmsen, or open it on the CipherChess analysis board to review it with the Stockfish engine.