Vladimir Modric vs Roger Burow
2014 · Result 1–0 · Hungarian Opening: Wiedenhagen-Beta Gambit (A07).
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Game details
- White
- Vladimir Modric (1888)
- Black
- Roger Burow (1628)
- Result
- 1–0
- Year
- 2014
- Opening
- Hungarian Opening: Wiedenhagen-Beta Gambit (A07)
About this chess game
This chess game between Vladimir Modric (1888) and Roger Burow (1628) was played in 2014 and finished 1–0. The opening was the Hungarian Opening: Wiedenhagen-Beta Gambit (A07). You can replay the full game move by move on the interactive board above, or open it on the CipherChess analysis board to study every move with the Stockfish engine.
Looking for more Vladimir Modric games or Roger Burow games? This Vladimir Modric vs Roger Burow encounter is one of millions of chess games indexed in the CipherChess mega database. Browse both players' full records, the openings they play most, and head-to-head results, then load any game onto the board to prepare your own lines against the Hungarian Opening: Wiedenhagen-Beta Gambit.
Frequently asked questions
Who won Vladimir Modric vs Roger Burow?
Vladimir Modric vs Roger Burow (2014) finished 1–0, a win for Vladimir Modric.
What opening was played in Vladimir Modric vs Roger Burow?
The game opened with the Hungarian Opening: Wiedenhagen-Beta Gambit (ECO A07).
Can I replay this chess game move by move?
Yes. Use the interactive board on this page to step through every move of Vladimir Modric vs Roger Burow, or open it on the CipherChess analysis board to review it with the Stockfish engine.