Rushat Mingaliev vs Aleksandr V. Leontiev
Moscow RUS, 4. Open A, 2008 · Result 0–1 · Alekhine Defense (B03).
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Game details
- White
- Rushat Mingaliev (2116)
- Black
- Aleksandr V. Leontiev (2330)
- Result
- 0–1
- Event
- Moscow RUS, 4. Open A
- Year
- 2008
- Opening
- Alekhine Defense (B03)
About this chess game
This chess game between Rushat Mingaliev (2116) and Aleksandr V. Leontiev (2330) was played at Moscow RUS, 4. Open A in 2008 and finished 0–1. The opening was the Alekhine Defense (B03). You can replay the full game move by move on the interactive board above, or open it on the CipherChess analysis board to study every move with the Stockfish engine.
Looking for more Rushat Mingaliev games or Aleksandr V. Leontiev games? This Rushat Mingaliev vs Aleksandr V. Leontiev encounter is one of millions of chess games indexed in the CipherChess mega database. Browse both players' full records, the openings they play most, and head-to-head results, then load any game onto the board to prepare your own lines against the Alekhine Defense.
Frequently asked questions
Who won Rushat Mingaliev vs Aleksandr V. Leontiev?
Rushat Mingaliev vs Aleksandr V. Leontiev (2008) finished 0–1, a win for Aleksandr V. Leontiev.
What opening was played in Rushat Mingaliev vs Aleksandr V. Leontiev?
The game opened with the Alekhine Defense (ECO B03).
Can I replay this chess game move by move?
Yes. Use the interactive board on this page to step through every move of Rushat Mingaliev vs Aleksandr V. Leontiev, or open it on the CipherChess analysis board to review it with the Stockfish engine.