Clement Meunier vs Roman Oganisian
22. Saint-Affrique Open, 2014 · Result 0–1 · Benko Gambit Accepted: Fully Accepted Variation (A58).
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Game details
- White
- Clement Meunier (2132)
- Black
- Roman Oganisian (2245)
- Result
- 0–1
- Event
- 22. Saint-Affrique Open
- Year
- 2014
- Opening
- Benko Gambit Accepted: Fully Accepted Variation (A58)
About this chess game
This chess game between Clement Meunier (2132) and Roman Oganisian (2245) was played at 22. Saint-Affrique Open in 2014 and finished 0–1. The opening was the Benko Gambit Accepted: Fully Accepted Variation (A58). You can replay the full game move by move on the interactive board above, or open it on the CipherChess analysis board to study every move with the Stockfish engine.
Looking for more Clement Meunier games or Roman Oganisian games? This Clement Meunier vs Roman Oganisian encounter is one of millions of chess games indexed in the CipherChess mega database. Browse both players' full records, the openings they play most, and head-to-head results, then load any game onto the board to prepare your own lines against the Benko Gambit Accepted: Fully Accepted Variation.
Frequently asked questions
Who won Clement Meunier vs Roman Oganisian?
Clement Meunier vs Roman Oganisian (2014) finished 0–1, a win for Roman Oganisian.
What opening was played in Clement Meunier vs Roman Oganisian?
The game opened with the Benko Gambit Accepted: Fully Accepted Variation (ECO A58).
Can I replay this chess game move by move?
Yes. Use the interactive board on this page to step through every move of Clement Meunier vs Roman Oganisian, or open it on the CipherChess analysis board to review it with the Stockfish engine.