Zoltan Dr. Medvegy vs Alexander Berelowitsch
Bundesliga 2009-10, 2009 · Result ½–½ · Dutch Defense: Fianchetto Attack (A81).
Turn this game into your next win
Replay Zoltan Dr. Medvegy vs Alexander Berelowitsch with deep analysis, save the moments that matter, fold the ideas into your own opening repertoire, and drill the positions until they're second nature. CipherChess turns the games you study into the results you get — free to start.
Start Free on CipherChessMore Games By These Players
Game details
- White
- Zoltan Dr. Medvegy (2556)
- Black
- Alexander Berelowitsch (2551)
- Result
- ½–½
- Event
- Bundesliga 2009-10
- Year
- 2009
- Opening
- Dutch Defense: Fianchetto Attack (A81)
About this chess game
This chess game between Zoltan Dr. Medvegy (2556) and Alexander Berelowitsch (2551) was played at Bundesliga 2009-10 in 2009 and finished ½–½. The opening was the Dutch Defense: Fianchetto Attack (A81). You can replay the full game move by move on the interactive board above, or open it on the CipherChess analysis board to study every move with the Stockfish engine.
Looking for more Zoltan Dr. Medvegy games or Alexander Berelowitsch games? This Zoltan Dr. Medvegy vs Alexander Berelowitsch encounter is one of millions of chess games indexed in the CipherChess mega database. Browse both players' full records, the openings they play most, and head-to-head results, then load any game onto the board to prepare your own lines against the Dutch Defense: Fianchetto Attack.
Frequently asked questions
Who won Zoltan Dr. Medvegy vs Alexander Berelowitsch?
Zoltan Dr. Medvegy vs Alexander Berelowitsch (2009) finished ½–½, and the game was drawn.
What opening was played in Zoltan Dr. Medvegy vs Alexander Berelowitsch?
The game opened with the Dutch Defense: Fianchetto Attack (ECO A81).
Can I replay this chess game move by move?
Yes. Use the interactive board on this page to step through every move of Zoltan Dr. Medvegy vs Alexander Berelowitsch, or open it on the CipherChess analysis board to review it with the Stockfish engine.