Nathan McDonald vs Zi Han Goh
London Classic Open 2019, 2019 · Result 1–0 · Sicilian Defense: Moscow Variation (B51).
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Game details
- White
- Nathan McDonald (2412)
- Black
- Zi Han Goh (2094)
- Result
- 1–0
- Event
- London Classic Open 2019
- Year
- 2019
- Opening
- Sicilian Defense: Moscow Variation (B51)
About this chess game
This chess game between Nathan McDonald (2412) and Zi Han Goh (2094) was played at London Classic Open 2019 in 2019 and finished 1–0. The opening was the Sicilian Defense: Moscow Variation (B51). You can replay the full game move by move on the interactive board above, or open it on the CipherChess analysis board to study every move with the Stockfish engine.
Looking for more Nathan McDonald games or Zi Han Goh games? This Nathan McDonald vs Zi Han Goh encounter is one of millions of chess games indexed in the CipherChess mega database. Browse both players' full records, the openings they play most, and head-to-head results, then load any game onto the board to prepare your own lines against the Sicilian Defense: Moscow Variation.
Frequently asked questions
Who won Nathan McDonald vs Zi Han Goh?
Nathan McDonald vs Zi Han Goh (2019) finished 1–0, a win for Nathan McDonald.
What opening was played in Nathan McDonald vs Zi Han Goh?
The game opened with the Sicilian Defense: Moscow Variation (ECO B51).
Can I replay this chess game move by move?
Yes. Use the interactive board on this page to step through every move of Nathan McDonald vs Zi Han Goh, or open it on the CipherChess analysis board to review it with the Stockfish engine.