Wolfgang Mai vs Lukas Edy Santoso
AA/C22/Pr/O, 2020 · Result 0–1 · Sicilian Defense: Najdorf Variation, Poisoned Pawn Variation (B97).
Turn this game into your next win
Replay Wolfgang Mai vs Lukas Edy Santoso with deep analysis, save the moments that matter, fold the ideas into your own opening repertoire, and drill the positions until they're second nature. CipherChess turns the games you study into the results you get — free to start.
Start Free on CipherChessMore Games By These Players
Game details
- White
- Wolfgang Mai (1814)
- Black
- Lukas Edy Santoso
- Result
- 0–1
- Event
- AA/C22/Pr/O
- Year
- 2020
- Opening
- Sicilian Defense: Najdorf Variation, Poisoned Pawn Variation (B97)
About this chess game
This chess game between Wolfgang Mai (1814) and Lukas Edy Santoso was played at AA/C22/Pr/O in 2020 and finished 0–1. The opening was the Sicilian Defense: Najdorf Variation, Poisoned Pawn Variation (B97). You can replay the full game move by move on the interactive board above, or open it on the CipherChess analysis board to study every move with the Stockfish engine.
Looking for more Wolfgang Mai games or Lukas Edy Santoso games? This Wolfgang Mai vs Lukas Edy Santoso encounter is one of millions of chess games indexed in the CipherChess mega database. Browse both players' full records, the openings they play most, and head-to-head results, then load any game onto the board to prepare your own lines against the Sicilian Defense: Najdorf Variation, Poisoned Pawn Variation.
Frequently asked questions
Who won Wolfgang Mai vs Lukas Edy Santoso?
Wolfgang Mai vs Lukas Edy Santoso (2020) finished 0–1, a win for Lukas Edy Santoso.
What opening was played in Wolfgang Mai vs Lukas Edy Santoso?
The game opened with the Sicilian Defense: Najdorf Variation, Poisoned Pawn Variation (ECO B97).
Can I replay this chess game move by move?
Yes. Use the interactive board on this page to step through every move of Wolfgang Mai vs Lukas Edy Santoso, or open it on the CipherChess analysis board to review it with the Stockfish engine.