Reijo Maekelae vs Alexander Iordanov Todorov
1988 · Result 0–1 · Queen's Pawn Game: Zukertort Variation (D02).
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Game details
- White
- Reijo Maekelae (1820)
- Black
- Alexander Iordanov Todorov (2020)
- Result
- 0–1
- Year
- 1988
- Opening
- Queen's Pawn Game: Zukertort Variation (D02)
About this chess game
This chess game between Reijo Maekelae (1820) and Alexander Iordanov Todorov (2020) was played in 1988 and finished 0–1. The opening was the Queen's Pawn Game: Zukertort Variation (D02). You can replay the full game move by move on the interactive board above, or open it on the CipherChess analysis board to study every move with the Stockfish engine.
Looking for more Reijo Maekelae games or Alexander Iordanov Todorov games? This Reijo Maekelae vs Alexander Iordanov Todorov encounter is one of millions of chess games indexed in the CipherChess mega database. Browse both players' full records, the openings they play most, and head-to-head results, then load any game onto the board to prepare your own lines against the Queen's Pawn Game: Zukertort Variation.
Frequently asked questions
Who won Reijo Maekelae vs Alexander Iordanov Todorov?
Reijo Maekelae vs Alexander Iordanov Todorov (1988) finished 0–1, a win for Alexander Iordanov Todorov.
What opening was played in Reijo Maekelae vs Alexander Iordanov Todorov?
The game opened with the Queen's Pawn Game: Zukertort Variation (ECO D02).
Can I replay this chess game move by move?
Yes. Use the interactive board on this page to step through every move of Reijo Maekelae vs Alexander Iordanov Todorov, or open it on the CipherChess analysis board to review it with the Stockfish engine.