Viktor Lukanov vs Alexander Antonov
2013 · Result 1–0 · Indian Defense: Normal Variation (A50).
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Game details
- White
- Viktor Lukanov (2192)
- Black
- Alexander Antonov (2077)
- Result
- 1–0
- Year
- 2013
- Opening
- Indian Defense: Normal Variation (A50)
About this chess game
This chess game between Viktor Lukanov (2192) and Alexander Antonov (2077) was played in 2013 and finished 1–0. The opening was the Indian Defense: Normal Variation (A50). You can replay the full game move by move on the interactive board above, or open it on the CipherChess analysis board to study every move with the Stockfish engine.
Looking for more Viktor Lukanov games or Alexander Antonov games? This Viktor Lukanov vs Alexander Antonov encounter is one of millions of chess games indexed in the CipherChess mega database. Browse both players' full records, the openings they play most, and head-to-head results, then load any game onto the board to prepare your own lines against the Indian Defense: Normal Variation.
Frequently asked questions
Who won Viktor Lukanov vs Alexander Antonov?
Viktor Lukanov vs Alexander Antonov (2013) finished 1–0, a win for Viktor Lukanov.
What opening was played in Viktor Lukanov vs Alexander Antonov?
The game opened with the Indian Defense: Normal Variation (ECO A50).
Can I replay this chess game move by move?
Yes. Use the interactive board on this page to step through every move of Viktor Lukanov vs Alexander Antonov, or open it on the CipherChess analysis board to review it with the Stockfish engine.