Peter Lukacs vs Bela Perenyi
Budapest, 1988 · Result 1–0 · Benoni Defense: Taimanov Variation (A67).
Turn this game into your next win
Replay Peter Lukacs vs Bela Perenyi with deep analysis, save the moments that matter, fold the ideas into your own opening repertoire, and drill the positions until they're second nature. CipherChess turns the games you study into the results you get — free to start.
Start Free on CipherChessMore Games By These Players
Game details
- White
- Peter Lukacs (2490)
- Black
- Bela Perenyi (2370)
- Result
- 1–0
- Event
- Budapest
- Year
- 1988
- Opening
- Benoni Defense: Taimanov Variation (A67)
About this chess game
This chess game between Peter Lukacs (2490) and Bela Perenyi (2370) was played at Budapest in 1988 and finished 1–0. The opening was the Benoni Defense: Taimanov Variation (A67). You can replay the full game move by move on the interactive board above, or open it on the CipherChess analysis board to study every move with the Stockfish engine.
Looking for more Peter Lukacs games or Bela Perenyi games? This Peter Lukacs vs Bela Perenyi encounter is one of millions of chess games indexed in the CipherChess mega database. Browse both players' full records, the openings they play most, and head-to-head results, then load any game onto the board to prepare your own lines against the Benoni Defense: Taimanov Variation.
Frequently asked questions
Who won Peter Lukacs vs Bela Perenyi?
Peter Lukacs vs Bela Perenyi (1988) finished 1–0, a win for Peter Lukacs.
What opening was played in Peter Lukacs vs Bela Perenyi?
The game opened with the Benoni Defense: Taimanov Variation (ECO A67).
Can I replay this chess game move by move?
Yes. Use the interactive board on this page to step through every move of Peter Lukacs vs Bela Perenyi, or open it on the CipherChess analysis board to review it with the Stockfish engine.