Luz Adriana Lugo Lozano vs Andrea Raigosa Lopez
2013 · Result 1–0 · Queen's Pawn Game: Zukertort Variation (D02).
Turn this game into your next win
Replay Luz Adriana Lugo Lozano vs Andrea Raigosa Lopez with deep analysis, save the moments that matter, fold the ideas into your own opening repertoire, and drill the positions until they're second nature. CipherChess turns the games you study into the results you get — free to start.
Start Free on CipherChessMore Games By These Players
Game details
- White
- Luz Adriana Lugo Lozano (1918)
- Black
- Andrea Raigosa Lopez (1843)
- Result
- 1–0
- Year
- 2013
- Opening
- Queen's Pawn Game: Zukertort Variation (D02)
About this chess game
This chess game between Luz Adriana Lugo Lozano (1918) and Andrea Raigosa Lopez (1843) was played in 2013 and finished 1–0. The opening was the Queen's Pawn Game: Zukertort Variation (D02). You can replay the full game move by move on the interactive board above, or open it on the CipherChess analysis board to study every move with the Stockfish engine.
Looking for more Luz Adriana Lugo Lozano games or Andrea Raigosa Lopez games? This Luz Adriana Lugo Lozano vs Andrea Raigosa Lopez encounter is one of millions of chess games indexed in the CipherChess mega database. Browse both players' full records, the openings they play most, and head-to-head results, then load any game onto the board to prepare your own lines against the Queen's Pawn Game: Zukertort Variation.
Frequently asked questions
Who won Luz Adriana Lugo Lozano vs Andrea Raigosa Lopez?
Luz Adriana Lugo Lozano vs Andrea Raigosa Lopez (2013) finished 1–0, a win for Luz Adriana Lugo Lozano.
What opening was played in Luz Adriana Lugo Lozano vs Andrea Raigosa Lopez?
The game opened with the Queen's Pawn Game: Zukertort Variation (ECO D02).
Can I replay this chess game move by move?
Yes. Use the interactive board on this page to step through every move of Luz Adriana Lugo Lozano vs Andrea Raigosa Lopez, or open it on the CipherChess analysis board to review it with the Stockfish engine.