William Li vs Roman Sapozhnikov
Oakville Winter Open, 2019 · Result 1–0 · Sicilian Defense: Taimanov Variation, Bastrikov Variation (B49).
Turn this game into your next win
Replay William Li vs Roman Sapozhnikov with deep analysis, save the moments that matter, fold the ideas into your own opening repertoire, and drill the positions until they're second nature. CipherChess turns the games you study into the results you get — free to start.
Start Free on CipherChessMore Games By These Players
Game details
- White
- William Li (2269)
- Black
- Roman Sapozhnikov (2246)
- Result
- 1–0
- Event
- Oakville Winter Open
- Year
- 2019
- Opening
- Sicilian Defense: Taimanov Variation, Bastrikov Variation (B49)
About this chess game
This chess game between William Li (2269) and Roman Sapozhnikov (2246) was played at Oakville Winter Open in 2019 and finished 1–0. The opening was the Sicilian Defense: Taimanov Variation, Bastrikov Variation (B49). You can replay the full game move by move on the interactive board above, or open it on the CipherChess analysis board to study every move with the Stockfish engine.
Looking for more William Li games or Roman Sapozhnikov games? This William Li vs Roman Sapozhnikov encounter is one of millions of chess games indexed in the CipherChess mega database. Browse both players' full records, the openings they play most, and head-to-head results, then load any game onto the board to prepare your own lines against the Sicilian Defense: Taimanov Variation, Bastrikov Variation.
Frequently asked questions
Who won William Li vs Roman Sapozhnikov?
William Li vs Roman Sapozhnikov (2019) finished 1–0, a win for William Li.
What opening was played in William Li vs Roman Sapozhnikov?
The game opened with the Sicilian Defense: Taimanov Variation, Bastrikov Variation (ECO B49).
Can I replay this chess game move by move?
Yes. Use the interactive board on this page to step through every move of William Li vs Roman Sapozhnikov, or open it on the CipherChess analysis board to review it with the Stockfish engine.