Jony Wilson Leon Valdes vs Yu Dong Deng
42. Barbera Open 2019, 2019 · Result 1–0 · Queen's Pawn Game: Zukertort Variation (D02).
Turn this game into your next win
Replay Jony Wilson Leon Valdes vs Yu Dong Deng with deep analysis, save the moments that matter, fold the ideas into your own opening repertoire, and drill the positions until they're second nature. CipherChess turns the games you study into the results you get — free to start.
Start Free on CipherChessMore Games By These Players
Game details
- White
- Jony Wilson Leon Valdes (2364)
- Black
- Yu Dong Deng (1900)
- Result
- 1–0
- Event
- 42. Barbera Open 2019
- Year
- 2019
- Opening
- Queen's Pawn Game: Zukertort Variation (D02)
About this chess game
This chess game between Jony Wilson Leon Valdes (2364) and Yu Dong Deng (1900) was played at 42. Barbera Open 2019 in 2019 and finished 1–0. The opening was the Queen's Pawn Game: Zukertort Variation (D02). You can replay the full game move by move on the interactive board above, or open it on the CipherChess analysis board to study every move with the Stockfish engine.
Looking for more Jony Wilson Leon Valdes games or Yu Dong Deng games? This Jony Wilson Leon Valdes vs Yu Dong Deng encounter is one of millions of chess games indexed in the CipherChess mega database. Browse both players' full records, the openings they play most, and head-to-head results, then load any game onto the board to prepare your own lines against the Queen's Pawn Game: Zukertort Variation.
Frequently asked questions
Who won Jony Wilson Leon Valdes vs Yu Dong Deng?
Jony Wilson Leon Valdes vs Yu Dong Deng (2019) finished 1–0, a win for Jony Wilson Leon Valdes.
What opening was played in Jony Wilson Leon Valdes vs Yu Dong Deng?
The game opened with the Queen's Pawn Game: Zukertort Variation (ECO D02).
Can I replay this chess game move by move?
Yes. Use the interactive board on this page to step through every move of Jony Wilson Leon Valdes vs Yu Dong Deng, or open it on the CipherChess analysis board to review it with the Stockfish engine.