Ioanis Lentzos vs Conor O`Donnell
4NCL 2014-15, 2015 · Result 0–1 · Sicilian Defense: Moscow Variation (B51).
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Game details
- White
- Ioanis Lentzos (2031)
- Black
- Conor O`Donnell (2185)
- Result
- 0–1
- Event
- 4NCL 2014-15
- Year
- 2015
- Opening
- Sicilian Defense: Moscow Variation (B51)
About this chess game
This chess game between Ioanis Lentzos (2031) and Conor O`Donnell (2185) was played at 4NCL 2014-15 in 2015 and finished 0–1. The opening was the Sicilian Defense: Moscow Variation (B51). You can replay the full game move by move on the interactive board above, or open it on the CipherChess analysis board to study every move with the Stockfish engine.
Looking for more Ioanis Lentzos games or Conor O`Donnell games? This Ioanis Lentzos vs Conor O`Donnell encounter is one of millions of chess games indexed in the CipherChess mega database. Browse both players' full records, the openings they play most, and head-to-head results, then load any game onto the board to prepare your own lines against the Sicilian Defense: Moscow Variation.
Frequently asked questions
Who won Ioanis Lentzos vs Conor O`Donnell?
Ioanis Lentzos vs Conor O`Donnell (2015) finished 0–1, a win for Conor O`Donnell.
What opening was played in Ioanis Lentzos vs Conor O`Donnell?
The game opened with the Sicilian Defense: Moscow Variation (ECO B51).
Can I replay this chess game move by move?
Yes. Use the interactive board on this page to step through every move of Ioanis Lentzos vs Conor O`Donnell, or open it on the CipherChess analysis board to review it with the Stockfish engine.