Wiebe Lenstra vs Alexander Jongsma
Amsterdam AMRO Open, date unknown · Result 1–0 · Indian Defense: Normal Variation (A50).
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Game details
- White
- Wiebe Lenstra (1935)
- Black
- Alexander Jongsma (2300)
- Result
- 1–0
- Event
- Amsterdam AMRO Open
- Opening
- Indian Defense: Normal Variation (A50)
About this chess game
This chess game between Wiebe Lenstra (1935) and Alexander Jongsma (2300) was played at Amsterdam AMRO Open and finished 1–0. The opening was the Indian Defense: Normal Variation (A50). You can replay the full game move by move on the interactive board above, or open it on the CipherChess analysis board to study every move with the Stockfish engine.
Looking for more Wiebe Lenstra games or Alexander Jongsma games? This Wiebe Lenstra vs Alexander Jongsma encounter is one of millions of chess games indexed in the CipherChess mega database. Browse both players' full records, the openings they play most, and head-to-head results, then load any game onto the board to prepare your own lines against the Indian Defense: Normal Variation.
Frequently asked questions
Who won Wiebe Lenstra vs Alexander Jongsma?
Wiebe Lenstra vs Alexander Jongsma finished 1–0, a win for Wiebe Lenstra.
What opening was played in Wiebe Lenstra vs Alexander Jongsma?
The game opened with the Indian Defense: Normal Variation (ECO A50).
Can I replay this chess game move by move?
Yes. Use the interactive board on this page to step through every move of Wiebe Lenstra vs Alexander Jongsma, or open it on the CipherChess analysis board to review it with the Stockfish engine.