Martina Lazaro del Arco vs Luca Pontiroli
Sunway Sitges 2025, 2025 · Result ½–½ · Queen's Pawn Game: Zukertort Variation (D05).
Turn this game into your next win
Replay Martina Lazaro del Arco vs Luca Pontiroli with deep analysis, save the moments that matter, fold the ideas into your own opening repertoire, and drill the positions until they're second nature. CipherChess turns the games you study into the results you get — free to start.
Start Free on CipherChessMore Games By These Players
Game details
- White
- Martina Lazaro del Arco (1901)
- Black
- Luca Pontiroli (1690)
- Result
- ½–½
- Event
- Sunway Sitges 2025
- Year
- 2025
- Opening
- Queen's Pawn Game: Zukertort Variation (D05)
About this chess game
This chess game between Martina Lazaro del Arco (1901) and Luca Pontiroli (1690) was played at Sunway Sitges 2025 in 2025 and finished ½–½. The opening was the Queen's Pawn Game: Zukertort Variation (D05). You can replay the full game move by move on the interactive board above, or open it on the CipherChess analysis board to study every move with the Stockfish engine.
Looking for more Martina Lazaro del Arco games or Luca Pontiroli games? This Martina Lazaro del Arco vs Luca Pontiroli encounter is one of millions of chess games indexed in the CipherChess mega database. Browse both players' full records, the openings they play most, and head-to-head results, then load any game onto the board to prepare your own lines against the Queen's Pawn Game: Zukertort Variation.
Frequently asked questions
Who won Martina Lazaro del Arco vs Luca Pontiroli?
Martina Lazaro del Arco vs Luca Pontiroli (2025) finished ½–½, and the game was drawn.
What opening was played in Martina Lazaro del Arco vs Luca Pontiroli?
The game opened with the Queen's Pawn Game: Zukertort Variation (ECO D05).
Can I replay this chess game move by move?
Yes. Use the interactive board on this page to step through every move of Martina Lazaro del Arco vs Luca Pontiroli, or open it on the CipherChess analysis board to review it with the Stockfish engine.