Bogdan Lalic vs Oleg Zujev
London Classic Superrapid, 2016 · Result 1–0 · Old Indian Defense: Normal Variation (A55).
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Game details
- White
- Bogdan Lalic (2443)
- Black
- Oleg Zujev (2340)
- Result
- 1–0
- Event
- London Classic Superrapid
- Year
- 2016
- Opening
- Old Indian Defense: Normal Variation (A55)
About this chess game
This chess game between Bogdan Lalic (2443) and Oleg Zujev (2340) was played at London Classic Superrapid in 2016 and finished 1–0. The opening was the Old Indian Defense: Normal Variation (A55). You can replay the full game move by move on the interactive board above, or open it on the CipherChess analysis board to study every move with the Stockfish engine.
Looking for more Bogdan Lalic games or Oleg Zujev games? This Bogdan Lalic vs Oleg Zujev encounter is one of millions of chess games indexed in the CipherChess mega database. Browse both players' full records, the openings they play most, and head-to-head results, then load any game onto the board to prepare your own lines against the Old Indian Defense: Normal Variation.
Frequently asked questions
Who won Bogdan Lalic vs Oleg Zujev?
Bogdan Lalic vs Oleg Zujev (2016) finished 1–0, a win for Bogdan Lalic.
What opening was played in Bogdan Lalic vs Oleg Zujev?
The game opened with the Old Indian Defense: Normal Variation (ECO A55).
Can I replay this chess game move by move?
Yes. Use the interactive board on this page to step through every move of Bogdan Lalic vs Oleg Zujev, or open it on the CipherChess analysis board to review it with the Stockfish engine.