Bogdan Lalic vs Jugoslav Zarkovic
JUG Team Ch Cetinje, date unknown · Result 1–0 · Dutch Defense: Leningrad Variation, Warsaw Variation (A88).
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Game details
- White
- Bogdan Lalic (2475)
- Black
- Jugoslav Zarkovic (2400)
- Result
- 1–0
- Event
- JUG Team Ch Cetinje
- Opening
- Dutch Defense: Leningrad Variation, Warsaw Variation (A88)
About this chess game
This chess game between Bogdan Lalic (2475) and Jugoslav Zarkovic (2400) was played at JUG Team Ch Cetinje and finished 1–0. The opening was the Dutch Defense: Leningrad Variation, Warsaw Variation (A88). You can replay the full game move by move on the interactive board above, or open it on the CipherChess analysis board to study every move with the Stockfish engine.
Looking for more Bogdan Lalic games or Jugoslav Zarkovic games? This Bogdan Lalic vs Jugoslav Zarkovic encounter is one of millions of chess games indexed in the CipherChess mega database. Browse both players' full records, the openings they play most, and head-to-head results, then load any game onto the board to prepare your own lines against the Dutch Defense: Leningrad Variation, Warsaw Variation.
Frequently asked questions
Who won Bogdan Lalic vs Jugoslav Zarkovic?
Bogdan Lalic vs Jugoslav Zarkovic finished 1–0, a win for Bogdan Lalic.
What opening was played in Bogdan Lalic vs Jugoslav Zarkovic?
The game opened with the Dutch Defense: Leningrad Variation, Warsaw Variation (ECO A88).
Can I replay this chess game move by move?
Yes. Use the interactive board on this page to step through every move of Bogdan Lalic vs Jugoslav Zarkovic, or open it on the CipherChess analysis board to review it with the Stockfish engine.