Bogdan Lalic vs Connor Passin
Wroclaw Open 2019, 2019 · Result 1–0 · English Opening: Symmetrical Variation, Mecking Variation (A39).
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Game details
- White
- Bogdan Lalic (2420)
- Black
- Connor Passin (1639)
- Result
- 1–0
- Event
- Wroclaw Open 2019
- Year
- 2019
- Opening
- English Opening: Symmetrical Variation, Mecking Variation (A39)
About this chess game
This chess game between Bogdan Lalic (2420) and Connor Passin (1639) was played at Wroclaw Open 2019 in 2019 and finished 1–0. The opening was the English Opening: Symmetrical Variation, Mecking Variation (A39). You can replay the full game move by move on the interactive board above, or open it on the CipherChess analysis board to study every move with the Stockfish engine.
Looking for more Bogdan Lalic games or Connor Passin games? This Bogdan Lalic vs Connor Passin encounter is one of millions of chess games indexed in the CipherChess mega database. Browse both players' full records, the openings they play most, and head-to-head results, then load any game onto the board to prepare your own lines against the English Opening: Symmetrical Variation, Mecking Variation.
Frequently asked questions
Who won Bogdan Lalic vs Connor Passin?
Bogdan Lalic vs Connor Passin (2019) finished 1–0, a win for Bogdan Lalic.
What opening was played in Bogdan Lalic vs Connor Passin?
The game opened with the English Opening: Symmetrical Variation, Mecking Variation (ECO A39).
Can I replay this chess game move by move?
Yes. Use the interactive board on this page to step through every move of Bogdan Lalic vs Connor Passin, or open it on the CipherChess analysis board to review it with the Stockfish engine.