Bogdan Lalic vs Jean Pascot
8. Rohde Open, 2008 · Result 1–0 · King's Indian Defense: Orthodox Variation (E91).
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Game details
- White
- Bogdan Lalic (2531)
- Black
- Jean Pascot (1882)
- Result
- 1–0
- Event
- 8. Rohde Open
- Year
- 2008
- Opening
- King's Indian Defense: Orthodox Variation (E91)
About this chess game
This chess game between Bogdan Lalic (2531) and Jean Pascot (1882) was played at 8. Rohde Open in 2008 and finished 1–0. The opening was the King's Indian Defense: Orthodox Variation (E91). You can replay the full game move by move on the interactive board above, or open it on the CipherChess analysis board to study every move with the Stockfish engine.
Looking for more Bogdan Lalic games or Jean Pascot games? This Bogdan Lalic vs Jean Pascot encounter is one of millions of chess games indexed in the CipherChess mega database. Browse both players' full records, the openings they play most, and head-to-head results, then load any game onto the board to prepare your own lines against the King's Indian Defense: Orthodox Variation.
Frequently asked questions
Who won Bogdan Lalic vs Jean Pascot?
Bogdan Lalic vs Jean Pascot (2008) finished 1–0, a win for Bogdan Lalic.
What opening was played in Bogdan Lalic vs Jean Pascot?
The game opened with the King's Indian Defense: Orthodox Variation (ECO E91).
Can I replay this chess game move by move?
Yes. Use the interactive board on this page to step through every move of Bogdan Lalic vs Jean Pascot, or open it on the CipherChess analysis board to review it with the Stockfish engine.