Bogdan Lalic vs Michael W Healey
6. Jessie Gilbert Open 2013, 2013 · Result 1–0 · Indian Defense: Normal Variation (A50).
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Game details
- White
- Bogdan Lalic (2484)
- Black
- Michael W Healey (2108)
- Result
- 1–0
- Event
- 6. Jessie Gilbert Open 2013
- Year
- 2013
- Opening
- Indian Defense: Normal Variation (A50)
About this chess game
This chess game between Bogdan Lalic (2484) and Michael W Healey (2108) was played at 6. Jessie Gilbert Open 2013 in 2013 and finished 1–0. The opening was the Indian Defense: Normal Variation (A50). You can replay the full game move by move on the interactive board above, or open it on the CipherChess analysis board to study every move with the Stockfish engine.
Looking for more Bogdan Lalic games or Michael W Healey games? This Bogdan Lalic vs Michael W Healey encounter is one of millions of chess games indexed in the CipherChess mega database. Browse both players' full records, the openings they play most, and head-to-head results, then load any game onto the board to prepare your own lines against the Indian Defense: Normal Variation.
Frequently asked questions
Who won Bogdan Lalic vs Michael W Healey?
Bogdan Lalic vs Michael W Healey (2013) finished 1–0, a win for Bogdan Lalic.
What opening was played in Bogdan Lalic vs Michael W Healey?
The game opened with the Indian Defense: Normal Variation (ECO A50).
Can I replay this chess game move by move?
Yes. Use the interactive board on this page to step through every move of Bogdan Lalic vs Michael W Healey, or open it on the CipherChess analysis board to review it with the Stockfish engine.