Bogdan Lalic vs Jose Felix Dominguez Corrales
2007 · Result 1–0 · Old Indian Defense: Normal Variation (A55).
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Game details
- White
- Bogdan Lalic (2522)
- Black
- Jose Felix Dominguez Corrales (1892)
- Result
- 1–0
- Year
- 2007
- Opening
- Old Indian Defense: Normal Variation (A55)
About this chess game
This chess game between Bogdan Lalic (2522) and Jose Felix Dominguez Corrales (1892) was played in 2007 and finished 1–0. The opening was the Old Indian Defense: Normal Variation (A55). You can replay the full game move by move on the interactive board above, or open it on the CipherChess analysis board to study every move with the Stockfish engine.
Looking for more Bogdan Lalic games or Jose Felix Dominguez Corrales games? This Bogdan Lalic vs Jose Felix Dominguez Corrales encounter is one of millions of chess games indexed in the CipherChess mega database. Browse both players' full records, the openings they play most, and head-to-head results, then load any game onto the board to prepare your own lines against the Old Indian Defense: Normal Variation.
Frequently asked questions
Who won Bogdan Lalic vs Jose Felix Dominguez Corrales?
Bogdan Lalic vs Jose Felix Dominguez Corrales (2007) finished 1–0, a win for Bogdan Lalic.
What opening was played in Bogdan Lalic vs Jose Felix Dominguez Corrales?
The game opened with the Old Indian Defense: Normal Variation (ECO A55).
Can I replay this chess game move by move?
Yes. Use the interactive board on this page to step through every move of Bogdan Lalic vs Jose Felix Dominguez Corrales, or open it on the CipherChess analysis board to review it with the Stockfish engine.