Alexander Lagunow vs V. Paranichev
USSR, 1989 · Result 1–0 · Catalan Opening: Open Defense (E04).
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Game details
- White
- Alexander Lagunow (2400)
- Black
- V. Paranichev
- Result
- 1–0
- Event
- USSR
- Year
- 1989
- Opening
- Catalan Opening: Open Defense (E04)
About this chess game
This chess game between Alexander Lagunow (2400) and V. Paranichev was played at USSR in 1989 and finished 1–0. The opening was the Catalan Opening: Open Defense (E04). You can replay the full game move by move on the interactive board above, or open it on the CipherChess analysis board to study every move with the Stockfish engine.
Looking for more Alexander Lagunow games or V. Paranichev games? This Alexander Lagunow vs V. Paranichev encounter is one of millions of chess games indexed in the CipherChess mega database. Browse both players' full records, the openings they play most, and head-to-head results, then load any game onto the board to prepare your own lines against the Catalan Opening: Open Defense.
Frequently asked questions
Who won Alexander Lagunow vs V. Paranichev?
Alexander Lagunow vs V. Paranichev (1989) finished 1–0, a win for Alexander Lagunow.
What opening was played in Alexander Lagunow vs V. Paranichev?
The game opened with the Catalan Opening: Open Defense (ECO E04).
Can I replay this chess game move by move?
Yes. Use the interactive board on this page to step through every move of Alexander Lagunow vs V. Paranichev, or open it on the CipherChess analysis board to review it with the Stockfish engine.