Markos Kazakos vs Ioannis Stamatis
Greek Youth Team Championship 2018, 2018 · Result 1–0 · Hungarian Opening: Wiedenhagen-Beta Gambit (A07).
Turn this game into your next win
Replay Markos Kazakos vs Ioannis Stamatis with deep analysis, save the moments that matter, fold the ideas into your own opening repertoire, and drill the positions until they're second nature. CipherChess turns the games you study into the results you get — free to start.
Start Free on CipherChessMore Games By These Players
Game details
- White
- Markos Kazakos (2054)
- Black
- Ioannis Stamatis (1847)
- Result
- 1–0
- Event
- Greek Youth Team Championship 2018
- Year
- 2018
- Opening
- Hungarian Opening: Wiedenhagen-Beta Gambit (A07)
About this chess game
This chess game between Markos Kazakos (2054) and Ioannis Stamatis (1847) was played at Greek Youth Team Championship 2018 in 2018 and finished 1–0. The opening was the Hungarian Opening: Wiedenhagen-Beta Gambit (A07). You can replay the full game move by move on the interactive board above, or open it on the CipherChess analysis board to study every move with the Stockfish engine.
Looking for more Markos Kazakos games or Ioannis Stamatis games? This Markos Kazakos vs Ioannis Stamatis encounter is one of millions of chess games indexed in the CipherChess mega database. Browse both players' full records, the openings they play most, and head-to-head results, then load any game onto the board to prepare your own lines against the Hungarian Opening: Wiedenhagen-Beta Gambit.
Frequently asked questions
Who won Markos Kazakos vs Ioannis Stamatis?
Markos Kazakos vs Ioannis Stamatis (2018) finished 1–0, a win for Markos Kazakos.
What opening was played in Markos Kazakos vs Ioannis Stamatis?
The game opened with the Hungarian Opening: Wiedenhagen-Beta Gambit (ECO A07).
Can I replay this chess game move by move?
Yes. Use the interactive board on this page to step through every move of Markos Kazakos vs Ioannis Stamatis, or open it on the CipherChess analysis board to review it with the Stockfish engine.