Alexander Kanikevich vs John Paul Wallace
NSW Ch, 1991 · Result 1–0 · English Opening: Symmetrical Variation (A30).
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Game details
- White
- Alexander Kanikevich (2345)
- Black
- John Paul Wallace (2340)
- Result
- 1–0
- Event
- NSW Ch
- Year
- 1991
- Opening
- English Opening: Symmetrical Variation (A30)
About this chess game
This chess game between Alexander Kanikevich (2345) and John Paul Wallace (2340) was played at NSW Ch in 1991 and finished 1–0. The opening was the English Opening: Symmetrical Variation (A30). You can replay the full game move by move on the interactive board above, or open it on the CipherChess analysis board to study every move with the Stockfish engine.
Looking for more Alexander Kanikevich games or John Paul Wallace games? This Alexander Kanikevich vs John Paul Wallace encounter is one of millions of chess games indexed in the CipherChess mega database. Browse both players' full records, the openings they play most, and head-to-head results, then load any game onto the board to prepare your own lines against the English Opening: Symmetrical Variation.
Frequently asked questions
Who won Alexander Kanikevich vs John Paul Wallace?
Alexander Kanikevich vs John Paul Wallace (1991) finished 1–0, a win for Alexander Kanikevich.
What opening was played in Alexander Kanikevich vs John Paul Wallace?
The game opened with the English Opening: Symmetrical Variation (ECO A30).
Can I replay this chess game move by move?
Yes. Use the interactive board on this page to step through every move of Alexander Kanikevich vs John Paul Wallace, or open it on the CipherChess analysis board to review it with the Stockfish engine.