Peter Jeute vs Alexander A. Yakimenko
4. South Bohemia Open, 2010 · Result 0–1 · Indian Defense: Knights Variation (A46).
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Game details
- White
- Peter Jeute (1969)
- Black
- Alexander A. Yakimenko (2194)
- Result
- 0–1
- Event
- 4. South Bohemia Open
- Year
- 2010
- Opening
- Indian Defense: Knights Variation (A46)
About this chess game
This chess game between Peter Jeute (1969) and Alexander A. Yakimenko (2194) was played at 4. South Bohemia Open in 2010 and finished 0–1. The opening was the Indian Defense: Knights Variation (A46). You can replay the full game move by move on the interactive board above, or open it on the CipherChess analysis board to study every move with the Stockfish engine.
Looking for more Peter Jeute games or Alexander A. Yakimenko games? This Peter Jeute vs Alexander A. Yakimenko encounter is one of millions of chess games indexed in the CipherChess mega database. Browse both players' full records, the openings they play most, and head-to-head results, then load any game onto the board to prepare your own lines against the Indian Defense: Knights Variation.
Frequently asked questions
Who won Peter Jeute vs Alexander A. Yakimenko?
Peter Jeute vs Alexander A. Yakimenko (2010) finished 0–1, a win for Alexander A. Yakimenko.
What opening was played in Peter Jeute vs Alexander A. Yakimenko?
The game opened with the Indian Defense: Knights Variation (ECO A46).
Can I replay this chess game move by move?
Yes. Use the interactive board on this page to step through every move of Peter Jeute vs Alexander A. Yakimenko, or open it on the CipherChess analysis board to review it with the Stockfish engine.